(x-y)/(x²-xy-2y²) - 2/(3x+3y)

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(x-y)/(x²-xy-2y²) - 2/(3x+3y)
(x-y)/(x²-xy-2y²) - 2/(3x+3y)

(x-y)/(x²-xy-2y²) - 2/(3x+3y)
(x-y)/(x^2-xy-2y^2) - 2/(3x+3y)
=(x-y)/[(x+y)(x-2y)]-2/[3(x+y)]
=(3x-3y)/[3(x+y)(x-2y)]-(2x-4y)/[3(x+y)(x-2y)]
=(3x-3y-2x+4y)/[3(x+y)(x-2y)]
=(x+y)/[3(x+y)(x-2y)]
=1/[3x-6y]

（x-y)/(x-2y)(x+y)-2/3(x+y)
=(3x-3y)/3(x-2y)(x+y)-2(x-2y)/3(x-2y)(x+y)
=(x+y)/3(x-2y)(x+y)
=1/3(x-2y)

原式
=（3x²-3y²-2x²+2xy+4y²)/(x²-xy-2y²)(3x+3y)
=（x²+2xy+y²)/(x²-xy-2y²)(3x+3y)
=(x+y)²/(x²+xy-2xy-2y²)3(x+y)
=(x+y)/3[x(...

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原式
=（3x²-3y²-2x²+2xy+4y²)/(x²-xy-2y²)(3x+3y)
=（x²+2xy+y²)/(x²-xy-2y²)(3x+3y)
=(x+y)²/(x²+xy-2xy-2y²)3(x+y)
=(x+y)/3[x(x+y)-2y(x+y)]
=(x+y)/3(x+y)(x-2y)
=1/3(x-2y)
不知道你满意不
我写的比较详细
你看懂了之后可以简化点

收起

你是小学生吗？晕，同分就可以看出答案了，我看初中生都会！！

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