#define N 10#define s(x) x*x#define f(x) (x*x)main(){int i1,i2;i1=1000/s(N);i2=1000/f(N);printf("%d %d\n",i1,i2);}运行结果是?

#define #define PWM_PCR_PWMENAn(n) ((uint32_t)(((n&0x7) #define N 2 #define M N+1 #define K M+1*M/2#define N 2#define M N+1#define K M+1*M/2main(){int i;for(i=1;i #define getbit( b,n) (((b) & (1L define是什么意思 谁能解释下列c++中时钟的宏的含义#define ANALOG_CENTER_X (227)#define ANALOG_CENTER_Y (178)#define ANALOG_R (150)#define ANALOG_CENTER_R (10)#define ANALOG_HOUR_LEN (ANALOG_R-80)#define ANALOG_MINUTE_LEN (ANALOG_R-50)#define ANALOG_SECOND #define N 10#define s(x) x*x#define f(x) (x*x)main(){int i1,i2;i1=1000/s(N);i2=1000/f(N);printf(%d %d ,i1,i2);}运行结果是? C语言中 #define N 30 #define IFADOB(A,B) ((A)&&(B,0)) 括号匹配检验程序#include#include#define TRUE 1#define FALSE 0#define OK 1#define ERROR 0typedef char SElemType;typedef int Status;#define STACK_INIT_SIZE 100#define STACKINCREMENT 10typedef struct{SElemType *base;SElemType *top;int stacksize; C/C++:#define SIGN(n) (n==0?(n 英语翻译define('UC_CONNECT','mysql');define('UC_DBHOST','localhost');define('UC_DBUSER','root');define('UC_DBPW','sohu');define('UC_DBNAME','****');define('UC_DBCHARSET','gbk');define('UC_DBTABLEPRE','`dz7`.uc_');define('UC_DBCONNECT','0');define #define N 3 #define Y(n) ((N=1)*n) 则表达式2*（N+Y（5+1))的值是#define N 3 #define Y(n) ((N+1)*n) 则表达式2*（N+Y（5+1))的值是 #define N 2 #define M N+1 #define NUM (M+1)*M/2 main() {int I; for(I=1;I #include #define N 2#define M N+1#define NUM (M+1)*M/2main(){ int i;for(i=1;i 在C语言中为什么执行过 #define N 2 #define M N+1 #define NUM (M+1)*M/2以后,NUM的值是8而不是6 写出下列程序段的输出结果.#define A 10 #define B (A #define 比如说#define PI=3.4 warning C4700:local variable 'l' used without having been initialized#include stdio.h#include stdlib.h#define ERROR 0#define ok 1#define OVERFLOW -2#define list_init_size 100//线性表存储空间的初始分配量#define listincrement 10//线