若x,y满足y《根号下x-2+根号下2-x +4,化简y-4的绝对值-根号下y2-10y+25

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若x,y满足y《根号下x-2+根号下2-x +4,化简y-4的绝对值-根号下y2-10y+25

若x,y满足y《根号下x-2+根号下2-x +4,化简y-4的绝对值-根号下y2-10y+25
若x,y满足y《根号下x-2+根号下2-x +4,化简y-4的绝对值-根号下y2-10y+25

若x,y满足y《根号下x-2+根号下2-x +4,化简y-4的绝对值-根号下y2-10y+25
根号下则x-2>=0,x>=2
2-x>=0,x<=2
同时成立则x=2
所以y<=0+0+4
y<=4
所以y-4<=0
|y-4|=4-y
y<5
所以 |y-5|=5-y
所以原式=4-y-√(y-5)²
=4-y-|y-5|
=4-y+y-5
=-1

y《√(x-2)+√(2-x)+4
根据题意
x=2(根号下代数式值非负)
y《4
|y-4|-√(y²-10y+25)
=4-y-√(y-5)²
=4-y-(5-y)
=4-y-5+y
=-1

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